Consider using [NOT] EXISTS instead of [NOT] IN with a subquery (PE019)
Phil Factor explains why you should prefer use of [NOT] EXISTS over [NOT] IN, when comparing data sets using a subquery. While there is no longer any significant performance advantage, using NOT EXISTS will avoid unexpected results when the subquery’s source data contains NULL values.
It used to be that the EXISTS logical operator was faster than IN, when comparing data sets using a subquery. For example, in cases where the query had to perform a certain task, but only if the subquery returned any rows, then when evaluating WHERE [NOT] EXISTS (subquery), the database engine could quit searching as soon as it had found just one row, whereas WHERE [NOT] IN (subquery) would always collect all the results from the sub-query, before further processing.
However, the query optimizer now treats EXISTS and IN the same way, whenever it can, so you’re unlikely to see any significant performance differences. Nevertheless, you need to be cautious when using the NOT IN operator if the subquery’s source data contains NULL values. If so, you should consider using a NOT EXISTS operator instead of NOT IN, or recast the statement as a left outer join.
A recommendation to prefer use of [NOT] EXISTS over [NOT] IN is included as a code analysis rule in SQL Prompt (PE019).
Which performs better: EXISTS or IN….?
There are many ways of working out the differences between two data sets, but two of the most common are to use either the EXISTS
or the IN
logical operator. Imagine that we have two simple tables, one with all the common words in the English language (CommonWords
), and the other with a list of all the words in Bram Stoker’s ‘Dracula’ (WordsInDracula
). The TestExistsAndIn download includes the script to create these two tables and populate each one from its associated text file. It is useful, generally, to have tables like these in your sandbox server, for running tests while doing development work, though the book you use is your choice!
How many words occur in Dracula that aren’t common words? Assuming there are no NULL
values in the CommonWords.Word
column (more on this later), then the following queries will return the same result (1555 words), and have the same execution plan, which uses a Merge Join (Right Anti Semi Join) between the two tables.
1 2 3 4 5 6 7 8 9 10 11 |
--using NOT IN SELECT Count(*) FROM dbo.WordsInDracula WHERE word NOT IN (SELECT CommonWords.word FROM dbo.CommonWords); --Using NOT EXISTS SELECT Count(*) FROM dbo.WordsInDracula WHERE NOT EXISTS (SELECT * FROM dbo.CommonWords WHERE CommonWords.word = WordsInDracula.word); |
Listing 1
In short, the SQL Server optimizer treats either query in the same way, and they will perform the same too.
…or ANY, EXCEPT, INNER JOIN, OUTER JOIN or INTERSECT…?
What about all the other possible techniques, though, such as using ANY
, EXCEPT
, INNER
JOIN
, OUTER
JOIN
or INTERSECT
? Listing 2 shows seven further alternatives that I could think of easily, though there will be others.
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 |
--using ANY SELECT Count(*) FROM dbo.WordsInDracula WHERE NOT(WordsInDracula.word = ANY (SELECT word FROM commonwords )) ; --Right anti semi merge join --using EXCEPT SELECT Count(*) FROM ( SELECT word FROM dbo.WordsInDracula EXCEPT SELECT word FROM dbo.CommonWords ) AS JustTheUncommonOnes; --Right anti semi merge join --using LEFT OUTER JOIN SELECT Count(*) FROM dbo.WordsInDracula LEFT OUTER JOIN dbo.CommonWords ON CommonWords.word = WordsinDracula.word WHERE CommonWords.word IS NULL; --right outer merge join --using FULL OUTER JOIN SELECT Count(*) FROM dbo.WordsInDracula full OUTER JOIN dbo.CommonWords ON CommonWords.word = WordsinDracula.word WHERE CommonWords.word IS NULL; --Full outer join implemented as a merge join. --using intersect to get the difference SELECT (SELECT Count(*) FROM WordsInDracula)-Count(*) FROM ( SELECT word FROM dbo.WordsInDracula intersect SELECT word FROM dbo.CommonWords ) AS JustTheUncommonOnes; --inner merge join --using FULL OUTER JOIN syntax to get the difference SELECT Count(*)-(SELECT Count(*) FROM CommonWords) FROM dbo.WordsInDracula full OUTER JOIN dbo.CommonWords ON CommonWords.word = WordsinDracula.word --full outer merge join --using INNER JOIN syntax to get the difference SELECT (SELECT Count(*) FROM WordsinDracula)-Count(*) FROM dbo.WordsInDracula INNER JOIN dbo.CommonWords ON CommonWords.word = WordsinDracula.word --inner merge join |
Listing 2
The Test Harness
All nine queries give the same results, but does any one approach perform better? Let’s put them all in a simple test harness to see how long each version takes! Again, the code download file includes the test harness code, and all nine queries.
As the results show, although the queries look rather different, it’s generally just ‘syntactic sugar’ to the optimizer. However elegant your SQL, the optimizer merely shrugs and comes up with an efficient plan to execute it. In fact, the first four all use the exact same ‘right anti semi merge join’ execution plan, and all take the same amount of time.
We’ll check for variation by running the test several times. The INTERSECT
and INNER JOIN
queries both used an inner merge join, and were close. The two FULL OUTER JOIN
queries were a bit slower, but it was a close race.
The pitfall of NOT IN
There is a certain unreality in comparing sets with null values in them, but if it happens in the heat of everyday database reporting, things can go very wrong. If you have a NULL
value in the result of the subquery, or expression, that is passed to the IN
logical operator, it will give a reasonable response, and the same as the equivalent EXISTS
. However, NOT IN
behaves very differently.
Listing 3 demonstrates the problem. We insert three common and three uncommon words into a @someWord
table variable, and we want to know the number of common words that aren’t in our table variable.
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 |
SET NOCOUNT ON; DECLARE @someWord TABLE ( word NVARCHAR(35) NULL ); INSERT INTO @someWord ( word ) --three common words SELECT TOP 3 word FROM dbo.commonwords ORDER BY word DESC; -- three uncommon words INSERT INTO @someWord ( word ) VALUES ('flibberty'), ('jibberty'), ('flob'); SELECT [NOT EXISTS without NULL] = COUNT(*) FROM commonwords AS MyWords WHERE NOT EXISTS ( SELECT word FROM @someWord AS s WHERE s.word LIKE MyWords.word ); SELECT [NOT IN without NULL] = COUNT(*) FROM commonwords AS MyWords WHERE word NOT IN ( SELECT word FROM @someWord ); --Insert a NULL value INSERT INTO @someWord ( word ) VALUES (NULL); SELECT [NOT EXISTS with NULL] = COUNT(*) FROM commonwords AS MyWords WHERE NOT EXISTS ( SELECT word FROM @someWord AS s WHERE s.word LIKE MyWords.word ); SELECT [NOT IN with NULL] = COUNT(*) FROM commonwords AS MyWords WHERE word NOT IN ( SELECT word FROM @someWord ); |
Listing 3.
The NOT
IN
query, before we inserted a NULL
into @
someword, and both the NOT
EXISTS
queries, all tell us correctly that 60385 words are not in our table variable, because three are, and there are 60388 common words in all. However, if the subquery can return a NULL
, then NOT
IN
returns no rows at all.
NULL
really means ‘unknown’ rather than nothing, which is why any expression that compare to a NULL
value returns NULL
, or unknown.
Logically, SQL Server evaluates the subquery, replaces it with the list of values it returns, and then evaluates the [NOT]
IN
condition. For the IN
variant of our query, this does not cause a problem because it resolves to the following:
1 2 3 |
WHERE word = 'flibberty' OR word = 'jibberty' OR word = 'flob' OR word = 'zygotes' OR word = 'zygote' OR word = 'zydeco' OR word = NULL; |
This returns 3 rows, for the matches on the ‘z…’ words. The sting comes with NOT
IN
, which resolves to the following:
1 2 3 |
WHERE word <> 'flibberty' AND word <> 'jibberty'AND word <> 'flob' AND word <> 'zygotes' AND word <> 'zygote' AND word <> 'zydeco' AND word <> NULL; |
The AND
condition with a comparison to NULL
evaluates as ‘unknown’ , and so the expression will always return zero rows. This isn’t a bug; it is by design. You can argue that a NULL
shouldn’t be allowed in the any column where you want to use a NOT
IN
expression, but in our real working lives, these things can creep into table sources. It is worth being cautious. So, use the EXISTS
variant, or one of the others, or always remember to include a WHERE
clause in the IN
condition to eliminate the NULL
s.